Posttest pertemuan 4

Baris :
@M(i)(j) = @M(0)(0)+{(i-1)*N+(j-1)}*L
M(3)(2) = 0111(H)+{(3-1)*4+(2-1)}*4
= 0111(H)+36(D) -> 24(H)
= 0135(H)

Kolom :
@M[i][j] = @M[0][0] + {(j – 1) * K + (i – 1)} * L
M(3)(2) = 0111(H)+{(2-1)*9+(3-1)}
= 0111(H)+28(D) -> 16(H)
= 0111(H)+16(H)
= 012D(H)

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